Optimal. Leaf size=164 \[ \frac {a^{3/2} (11 B+14 C) \tan ^{-1}\left (\frac {\sqrt {a} \tan (c+d x)}{\sqrt {a \sec (c+d x)+a}}\right )}{8 d}+\frac {a^2 (11 B+14 C) \sin (c+d x)}{8 d \sqrt {a \sec (c+d x)+a}}+\frac {a^2 (7 B+6 C) \sin (c+d x) \cos (c+d x)}{12 d \sqrt {a \sec (c+d x)+a}}+\frac {a B \sin (c+d x) \cos ^2(c+d x) \sqrt {a \sec (c+d x)+a}}{3 d} \]
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Rubi [A] time = 0.47, antiderivative size = 164, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 6, integrand size = 42, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.143, Rules used = {4072, 4017, 4015, 3805, 3774, 203} \[ \frac {a^2 (11 B+14 C) \sin (c+d x)}{8 d \sqrt {a \sec (c+d x)+a}}+\frac {a^{3/2} (11 B+14 C) \tan ^{-1}\left (\frac {\sqrt {a} \tan (c+d x)}{\sqrt {a \sec (c+d x)+a}}\right )}{8 d}+\frac {a^2 (7 B+6 C) \sin (c+d x) \cos (c+d x)}{12 d \sqrt {a \sec (c+d x)+a}}+\frac {a B \sin (c+d x) \cos ^2(c+d x) \sqrt {a \sec (c+d x)+a}}{3 d} \]
Antiderivative was successfully verified.
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Rule 203
Rule 3774
Rule 3805
Rule 4015
Rule 4017
Rule 4072
Rubi steps
\begin {align*} \int \cos ^4(c+d x) (a+a \sec (c+d x))^{3/2} \left (B \sec (c+d x)+C \sec ^2(c+d x)\right ) \, dx &=\int \cos ^3(c+d x) (a+a \sec (c+d x))^{3/2} (B+C \sec (c+d x)) \, dx\\ &=\frac {a B \cos ^2(c+d x) \sqrt {a+a \sec (c+d x)} \sin (c+d x)}{3 d}+\frac {1}{3} \int \cos ^2(c+d x) \sqrt {a+a \sec (c+d x)} \left (\frac {1}{2} a (7 B+6 C)+\frac {3}{2} a (B+2 C) \sec (c+d x)\right ) \, dx\\ &=\frac {a^2 (7 B+6 C) \cos (c+d x) \sin (c+d x)}{12 d \sqrt {a+a \sec (c+d x)}}+\frac {a B \cos ^2(c+d x) \sqrt {a+a \sec (c+d x)} \sin (c+d x)}{3 d}+\frac {1}{8} (a (11 B+14 C)) \int \cos (c+d x) \sqrt {a+a \sec (c+d x)} \, dx\\ &=\frac {a^2 (11 B+14 C) \sin (c+d x)}{8 d \sqrt {a+a \sec (c+d x)}}+\frac {a^2 (7 B+6 C) \cos (c+d x) \sin (c+d x)}{12 d \sqrt {a+a \sec (c+d x)}}+\frac {a B \cos ^2(c+d x) \sqrt {a+a \sec (c+d x)} \sin (c+d x)}{3 d}+\frac {1}{16} (a (11 B+14 C)) \int \sqrt {a+a \sec (c+d x)} \, dx\\ &=\frac {a^2 (11 B+14 C) \sin (c+d x)}{8 d \sqrt {a+a \sec (c+d x)}}+\frac {a^2 (7 B+6 C) \cos (c+d x) \sin (c+d x)}{12 d \sqrt {a+a \sec (c+d x)}}+\frac {a B \cos ^2(c+d x) \sqrt {a+a \sec (c+d x)} \sin (c+d x)}{3 d}-\frac {\left (a^2 (11 B+14 C)\right ) \operatorname {Subst}\left (\int \frac {1}{a+x^2} \, dx,x,-\frac {a \tan (c+d x)}{\sqrt {a+a \sec (c+d x)}}\right )}{8 d}\\ &=\frac {a^{3/2} (11 B+14 C) \tan ^{-1}\left (\frac {\sqrt {a} \tan (c+d x)}{\sqrt {a+a \sec (c+d x)}}\right )}{8 d}+\frac {a^2 (11 B+14 C) \sin (c+d x)}{8 d \sqrt {a+a \sec (c+d x)}}+\frac {a^2 (7 B+6 C) \cos (c+d x) \sin (c+d x)}{12 d \sqrt {a+a \sec (c+d x)}}+\frac {a B \cos ^2(c+d x) \sqrt {a+a \sec (c+d x)} \sin (c+d x)}{3 d}\\ \end {align*}
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Mathematica [C] time = 11.90, size = 740, normalized size = 4.51 \[ a \left (\frac {B (\cos (c+d x)+1) \tan (c+d x) \sec ^2\left (\frac {c}{2}+\frac {d x}{2}\right ) \sqrt {a (\sec (c+d x)+1)} \, _2F_1\left (\frac {1}{2},3;\frac {3}{2};1-\sec (c+d x)\right )}{d (\sec (c+d x)+1)}+\frac {B (\cos (c+d x)+1) \tan (c+d x) \sec ^2\left (\frac {c}{2}+\frac {d x}{2}\right ) \sqrt {a (\sec (c+d x)+1)} \left (\cos (c+d x) \sqrt {1-\sec (c+d x)}+\tanh ^{-1}\left (\sqrt {1-\sec (c+d x)}\right )\right )}{4 d \sqrt {-\tan ^2(c+d x)} \sqrt {\sec (c+d x)+1}}+\frac {B (\cos (c+d x)+1) \sec ^2\left (\frac {c}{2}+\frac {d x}{2}\right ) \sqrt {a (\sec (c+d x)+1)} \left (\sec \left (\frac {1}{2} (c+d x)\right ) \sqrt {\sec (c+d x)+1} \left (7 \sin \left (\frac {1}{2} (c+d x)\right )-2 \sin \left (\frac {3}{2} (c+d x)\right )+3 \sin \left (\frac {5}{2} (c+d x)\right )+2 \sin \left (\frac {7}{2} (c+d x)\right )-3 \sqrt {2} \sin ^{-1}\left (\sqrt {2} \sin \left (\frac {1}{2} (c+d x)\right )\right ) \sqrt {\cos (c+d x)}\right )+\frac {12 \tan (c+d x) \left (\cos (c+d x) \sqrt {1-\sec (c+d x)}+\tanh ^{-1}\left (\sqrt {1-\sec (c+d x)}\right )\right )}{\sqrt {-\tan ^2(c+d x)}}\right )}{96 d \sqrt {\sec (c+d x)+1}}-\frac {C (\cos (c+d x)+1) \sec \left (\frac {1}{2} (c+d x)\right ) \sec ^2\left (\frac {c}{2}+\frac {d x}{2}\right ) \sqrt {a (\sec (c+d x)+1)} \left (\sin \left (\frac {1}{2} (c+d x)\right )-2 \sin \left (\frac {3}{2} (c+d x)\right )-\sin \left (\frac {5}{2} (c+d x)\right )+\sqrt {2} \sin ^{-1}\left (\sqrt {2} \sin \left (\frac {1}{2} (c+d x)\right )\right ) \sqrt {\cos (c+d x)}\right )}{16 d}+\frac {C \sin ^{-1}\left (\sqrt {2} \sin \left (\frac {1}{2} (c+d x)\right )\right ) \sqrt {\cos (c+d x)} (\cos (c+d x)+1) \sec \left (\frac {1}{2} (c+d x)\right ) \sec ^2\left (\frac {c}{2}+\frac {d x}{2}\right ) \sqrt {a (\sec (c+d x)+1)}}{2 \sqrt {2} d}+\frac {C (\cos (c+d x)+1) \tan (c+d x) \sec ^2\left (\frac {c}{2}+\frac {d x}{2}\right ) \sqrt {a (\sec (c+d x)+1)} \left (\cos (c+d x) \sqrt {1-\sec (c+d x)}+\tanh ^{-1}\left (\sqrt {1-\sec (c+d x)}\right )\right )}{2 d \sqrt {-\tan ^2(c+d x)} \sqrt {\sec (c+d x)+1}}\right ) \]
Antiderivative was successfully verified.
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fricas [A] time = 0.53, size = 360, normalized size = 2.20 \[ \left [\frac {3 \, {\left ({\left (11 \, B + 14 \, C\right )} a \cos \left (d x + c\right ) + {\left (11 \, B + 14 \, C\right )} a\right )} \sqrt {-a} \log \left (\frac {2 \, a \cos \left (d x + c\right )^{2} - 2 \, \sqrt {-a} \sqrt {\frac {a \cos \left (d x + c\right ) + a}{\cos \left (d x + c\right )}} \cos \left (d x + c\right ) \sin \left (d x + c\right ) + a \cos \left (d x + c\right ) - a}{\cos \left (d x + c\right ) + 1}\right ) + 2 \, {\left (8 \, B a \cos \left (d x + c\right )^{3} + 2 \, {\left (11 \, B + 6 \, C\right )} a \cos \left (d x + c\right )^{2} + 3 \, {\left (11 \, B + 14 \, C\right )} a \cos \left (d x + c\right )\right )} \sqrt {\frac {a \cos \left (d x + c\right ) + a}{\cos \left (d x + c\right )}} \sin \left (d x + c\right )}{48 \, {\left (d \cos \left (d x + c\right ) + d\right )}}, -\frac {3 \, {\left ({\left (11 \, B + 14 \, C\right )} a \cos \left (d x + c\right ) + {\left (11 \, B + 14 \, C\right )} a\right )} \sqrt {a} \arctan \left (\frac {\sqrt {\frac {a \cos \left (d x + c\right ) + a}{\cos \left (d x + c\right )}} \cos \left (d x + c\right )}{\sqrt {a} \sin \left (d x + c\right )}\right ) - {\left (8 \, B a \cos \left (d x + c\right )^{3} + 2 \, {\left (11 \, B + 6 \, C\right )} a \cos \left (d x + c\right )^{2} + 3 \, {\left (11 \, B + 14 \, C\right )} a \cos \left (d x + c\right )\right )} \sqrt {\frac {a \cos \left (d x + c\right ) + a}{\cos \left (d x + c\right )}} \sin \left (d x + c\right )}{24 \, {\left (d \cos \left (d x + c\right ) + d\right )}}\right ] \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [B] time = 7.93, size = 897, normalized size = 5.47 \[ \text {result too large to display} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [B] time = 1.87, size = 581, normalized size = 3.54 \[ -\frac {\left (33 B \left (\cos ^{2}\left (d x +c \right )\right ) \sin \left (d x +c \right ) \sqrt {2}\, \left (-\frac {2 \cos \left (d x +c \right )}{1+\cos \left (d x +c \right )}\right )^{\frac {5}{2}} \arctanh \left (\frac {\sqrt {-\frac {2 \cos \left (d x +c \right )}{1+\cos \left (d x +c \right )}}\, \sin \left (d x +c \right ) \sqrt {2}}{2 \cos \left (d x +c \right )}\right )+42 C \sqrt {2}\, \sin \left (d x +c \right ) \left (\cos ^{2}\left (d x +c \right )\right ) \arctanh \left (\frac {\sqrt {-\frac {2 \cos \left (d x +c \right )}{1+\cos \left (d x +c \right )}}\, \sin \left (d x +c \right ) \sqrt {2}}{2 \cos \left (d x +c \right )}\right ) \left (-\frac {2 \cos \left (d x +c \right )}{1+\cos \left (d x +c \right )}\right )^{\frac {5}{2}}+66 B \cos \left (d x +c \right ) \sin \left (d x +c \right ) \sqrt {2}\, \left (-\frac {2 \cos \left (d x +c \right )}{1+\cos \left (d x +c \right )}\right )^{\frac {5}{2}} \arctanh \left (\frac {\sqrt {-\frac {2 \cos \left (d x +c \right )}{1+\cos \left (d x +c \right )}}\, \sin \left (d x +c \right ) \sqrt {2}}{2 \cos \left (d x +c \right )}\right )+84 C \sqrt {2}\, \sin \left (d x +c \right ) \cos \left (d x +c \right ) \arctanh \left (\frac {\sqrt {-\frac {2 \cos \left (d x +c \right )}{1+\cos \left (d x +c \right )}}\, \sin \left (d x +c \right ) \sqrt {2}}{2 \cos \left (d x +c \right )}\right ) \left (-\frac {2 \cos \left (d x +c \right )}{1+\cos \left (d x +c \right )}\right )^{\frac {5}{2}}+33 B \left (-\frac {2 \cos \left (d x +c \right )}{1+\cos \left (d x +c \right )}\right )^{\frac {5}{2}} \arctanh \left (\frac {\sqrt {-\frac {2 \cos \left (d x +c \right )}{1+\cos \left (d x +c \right )}}\, \sin \left (d x +c \right ) \sqrt {2}}{2 \cos \left (d x +c \right )}\right ) \sqrt {2}\, \sin \left (d x +c \right )+42 C \arctanh \left (\frac {\sqrt {-\frac {2 \cos \left (d x +c \right )}{1+\cos \left (d x +c \right )}}\, \sin \left (d x +c \right ) \sqrt {2}}{2 \cos \left (d x +c \right )}\right ) \sqrt {2}\, \left (-\frac {2 \cos \left (d x +c \right )}{1+\cos \left (d x +c \right )}\right )^{\frac {5}{2}} \sin \left (d x +c \right )+64 B \left (\cos ^{6}\left (d x +c \right )\right )+112 B \left (\cos ^{5}\left (d x +c \right )\right )+96 C \left (\cos ^{5}\left (d x +c \right )\right )+88 B \left (\cos ^{4}\left (d x +c \right )\right )+240 C \left (\cos ^{4}\left (d x +c \right )\right )-264 B \left (\cos ^{3}\left (d x +c \right )\right )-336 C \left (\cos ^{3}\left (d x +c \right )\right )\right ) \sqrt {\frac {a \left (1+\cos \left (d x +c \right )\right )}{\cos \left (d x +c \right )}}\, a}{192 d \sin \left (d x +c \right ) \cos \left (d x +c \right )^{2}} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F(-1)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.01 \[ \int {\cos \left (c+d\,x\right )}^4\,\left (\frac {B}{\cos \left (c+d\,x\right )}+\frac {C}{{\cos \left (c+d\,x\right )}^2}\right )\,{\left (a+\frac {a}{\cos \left (c+d\,x\right )}\right )}^{3/2} \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F(-1)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
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